0=-16x^2+98x+39

Solution for 0=-16x^2+98x+39 equation:

0=-16x^2+98x+39

We move all terms to the left:

0-(-16x^2+98x+39)=0

We add all the numbers together, and all the variables

-(-16x^2+98x+39)=0

We get rid of parentheses

16x^2-98x-39=0

a = 16; b = -98; c = -39;
Δ = b2-4ac
Δ = -982-4·16·(-39)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-110}{2*16}=\frac{-12}{32}
=-3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+110}{2*16}=\frac{208}{32}
=6+1/2
$